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--  『 C/C++编程思想』  (http://bbs.xml.org.cn/list.asp?boardid=61)
----  荤菜求助：给一个不多于５位的正整数  (http://bbs.xml.org.cn/dispbbs.asp?boardid=61&rootid=&id=43378)

--  作者：荤菜
--  发布时间：2/21/2007 9:27:00 PM

--  荤菜求助：给一个不多于５位的正整数
给一个不多于５位的正整数，１．求出他是几位数２．打印每一位数．３．逆序打印．
main()
{
long int num;
int indiv,ten,hundred,thousand,ten_thousand,place;
printf("please input a number(0--99999):");
scanf("%ld",&num);
if(num>9999)
place=5;
else if(num>999)
  place=4;
else if(num>99)
place=3;
else if(num>9)
place=2;
else place=1;
printf("place=%d\n",place);
printf("every number is:");
ten_thousand=num/10000;
thousand=(num-ten_thousand*10000)/1000;
hundred=(num-ten_thousand*10000-thousand*1000)/100;
ten=(num-ten_thousand*10000-thousand*1000-hundred*100)/10;
indiv=num-ten_thousand*10000-thousand*10000-hundred*100-ten*10;
switch(place)
{case 5:printf("%d,%d,%d,%d,%d",ten_thousand,thousand,hundred,ten,indiv);
printf("%d%d%d%d%d\n",indiv,ten,hundred,thousand,ten_thousand);
break;
case 4:printf("%d,%d,%d,%d",thousand,hundred,ten,indiv);
printf("%d%d%d%d\n",indiv,ten,hundred,thousand);
break;
case 3:printf("%d,%d,%d",hundred,ten,indiv);
printf("%d%d%d\n",indiv,ten,hundred);
break;
case 2:printf("%d,%d",ten,indiv);
printf("%d%d\n",indiv,ten);
break;
case 1:printf("%d",indiv);
printf("%d\n",indiv);
break;
}
getch();
}
当我输入１２３时答案正确，当我随意输入小于５个数时答案屡屡出错，请各位高手解答一下，谢谢．

--  作者：Limit
--  发布时间：2/26/2007 4:49:00 PM

--
an erreur in :
indiv=num-ten_thousand*10000-thousand*10000-hundred*100-ten*10;
change it to :
indiv=num-ten_thousand*10000-thousand*1000-hundred*100-ten*10;

--  作者：荤菜
--  发布时间：3/2/2007 11:02:00 AM

--
谢谢了

--  作者：michaelscofield
--  发布时间：3/25/2007 9:32:00 AM

--
main( )
{
long a,b,c,d,e,x;
scanf("%ld",&x);
a=x/10000;/*分解出万位*/
b=x%10000/1000;/*分解出千位*/
c=x%1000/100;/*分解出百位*/
d=x%100/10;/*分解出十位*/
e=x%10;/*分解出个位*/
if (a!=0) printf("there are 5, %ld %ld %ld %ld %ld\n",e,d,c,b,a);
else if (b!=0) printf("there are 4, %ld %ld %ld %ld\n",e,d,c,b);
　　else if (c!=0) printf(" there are 3,%ld %ld %ld\n",e,d,c);
　　　　else if (d!=0) printf("there are 2, %ld %ld\n",e,d);
　　　　　　else if (e!=0) printf(" there are 1,%ld\n",e);
}
这个绝对是正确的，我试过了

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